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(A) The reaction of propene $(CH_3-CH=CH_2)$ with $HBr$ in the presence of an organic peroxide (like benzoyl peroxide) follows the anti-Markovnikov ad

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$1$-Bromopropane

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(A) The reaction of propene $(CH_3-CH=CH_2)$ with $HBr$ in the presence of an organic peroxide (like benzoyl peroxide) follows the anti-Markovnikov addition rule (also known as the Kharasch effect or peroxide effect). In this reaction,the bromine atom attaches to the carbon atom of the double bond that has more hydrogen atoms. Thus,the reaction proceeds as: $CH_3-CH=CH_2 + HBr \xrightarrow{	ext{peroxide}} CH_3-CH_2-CH_2Br$. The final product is $1$-bromopropane.

The product obtained by the reaction of propene with $HBr$ in the presence of peroxide is......

Similar Questions

The reaction of an alkene $X$ with bromine produces a compound $Y$,which has $22.22 \% \ C$,$3.71 \% \ H$ and $74.07 \% \ Br$. The ozonolysis of alkene $X$ gives only one product. The alkene $X$ is,
[Given,atomic mass of $C = 12$; $H = 1$; $Br = 80$ ]

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