Which of the following is the most stable car | vedclass

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Question

(B) The stability of a carbanion is increased by electron-withdrawing groups $(-EWG)$ and decreased by electron-donating groups $(-EDG)$ attached to t

Vedclass · Accepted Answer

$p-NO_2-C_6H_4-CH_2^-$

Vedclass · Answer

(B) The stability of a carbanion is increased by electron-withdrawing groups $(-EWG)$ and decreased by electron-donating groups $(-EDG)$ attached to the ring.The $-NO_2$ group is a strong electron-withdrawing group due to both $-I$ and $-M$ effects.The $-Cl$ group is electron-withdrawing due to the $-I$ effect but electron-donating due to the $+M$ effect (overall $-I$ dominates).The $-OCH_3$ group is a strong electron-donating group due to the $+M$ effect.The $-NO_2$ group stabilizes the negative charge on the carbanion most effectively through resonance and inductive effects.Therefore,$p-NO_2-C_6H_4-CH_2^-$ is the most stable carbanion.

List-$I$ (Carbocation)	List-$II$ (Type)
$A$. $CH_3-C^{+}(CH_3)-CH_3$	$I$. Secondary carbocation
$B$. $CH_3-C^{+}H-CH_3$	$II$. Methyl carbocation
$C$. $CH_3-CH_2^+$	$III$. Primary carbocation
$D$. $CH_3^+$	$IV$. Tertiary carbocation

Which of the following is the most stable carbanion?

Similar Questions

The correct order of stability is:

Which of the following orders regarding relative stability of free radicals is correct?

Match the following columns and select the correct option.

List-$I$ (Carbocation) List-$II$ (Type)

$A$. $CH_3-C^{+}(CH_3)-CH_3$ $I$. Secondary carbocation

$B$. $CH_3-C^{+}H-CH_3$ $II$. Methyl carbocation

$C$. $CH_3-CH_2^+$ $III$. Primary carbocation

$D$. $CH_3^+$ $IV$. Tertiary carbocation

In the given compound,$Cl$ will be liberated easily in the form of:

Which of the following cannot exist at room temperature?

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