Which of the following substances is the most | vedclass

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(D) The acidity of alcohols is determined by the stability of the conjugate base (alkoxide ion). Electron-withdrawing groups ($-I$ effect) stabilize t

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$CH_3-CH_2-CH_2-CHF-OH$

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(D) The acidity of alcohols is determined by the stability of the conjugate base (alkoxide ion). Electron-withdrawing groups ($-I$ effect) stabilize the negative charge on the oxygen atom,thereby increasing acidity. The strength of the $-I$ effect depends on the electronegativity of the substituent and its distance from the $-OH$ group. Fluorine $(F)$ has a stronger $-I$ effect than Iodine $(I)$. In option $(D)$,the fluorine atom is on the carbon directly attached to the $-OH$ group (alpha-carbon),which provides the strongest $-I$ effect due to the shortest distance. Therefore,$CH_3-CH_2-CH_2-CHF-OH$ is the most acidic.

Which of the following substances is the most acidic due to the hydroxyl proton?

Similar Questions

Which of the following compounds is the strongest acid?

Lucas test is associated with

What will be $A$,$B$,$C$,and $D$ in the following reaction sequence?
Cyclohexanol $\xrightarrow[H_2SO_4]{CrO_3} A$ $\xrightarrow[(ii) H_3O^+]{(i) CH_3MgI} B$ $\xrightarrow{\Delta, H_2SO_4} C$ $\xrightarrow[(ii) H_2O_2, NaOH]{(i) (BH_3)_2} D$

Which of the following orders is correct regarding the boiling point?

$CH_3 CH_2 OH \underset{\text{step-}1}{\stackrel{Cl_2}{\longrightarrow}} CH_3 CHO$ $\underset{\text{step-}2}{\stackrel{3 Cl_2}{\longrightarrow}} Cl_3 CCHO$
In the above reactions,the role of $Cl_2$ in step-$1$ and step-$2$ respectively is:

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