(D) The number of optical isomers is given by the formula $2^n$,where $n$ is the number of chiral centers.In the compound $CH_3CHBrCHBrCOOH$,there are

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(D) The number of optical isomers is given by the formula $2^n$,where $n$ is the number of chiral centers.In the compound $CH_3CHBrCHBrCOOH$,there are $2$ chiral centers (the two carbon atoms attached to the bromine atoms).Therefore,the number of optical isomers $= 2^2 = 4$.