Which isomer of a hydrocarbon with a molecula | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The molecular mass of the hydrocarbon is $72 \ u$. The general formula for an alkane is $C_nH_{2n+2}$.$12n + 1(2n+2) = 72 \implies 14n = 70 \impli

Vedclass · Accepted Answer

Neopentane

Vedclass · Answer

(C) The molecular mass of the hydrocarbon is $72 \ u$. The general formula for an alkane is $C_nH_{2n+2}$.$12n + 1(2n+2) = 72 \implies 14n = 70 \implies n = 5$.Thus,the hydrocarbon is pentane $(C_5H_{12})$.The isomers of pentane are $n$-pentane,isopentane,and neopentane.Neopentane ($2,2$-dimethylpropane) has all $12$ hydrogen atoms equivalent.Therefore,upon reaction with a halogen,it produces only one mono-substituted alkyl halide.

Which isomer of a hydrocarbon with a molecular mass of $72 \ u$ gives only one mono-substituted alkyl halide upon reaction with halogen?

Similar Questions

The product of a reaction at $773 \ K$ temperature is $C_7H_{16} + C_5H_{10}$. Identify the reactant and the type of reaction.

Identify the product $C$ in the following reaction:
$CH_{3}CH_{2}COOH$ $\xrightarrow{NaOH} A$ $\xrightarrow{NaOH, CaO, \Delta} B$ $\xrightarrow{HNO_{3}, \Delta} C$

Which of the following statements is true?

The general formula of a cycloalkane is

The compound $(X)$ on $(i)$ heating in the presence of anhydrous $AlCl_3$ and $HCl$ gas gives $2,4$-dimethylpentane, $(ii)$ aromatization gives toluene, and $(iii)$ cyclisation gives methylcyclohexane. The correct name of compound $(X)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module