Arrange the following acids in decreasing ord | vedclass

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(B) The acidity of carboxylic acids depends on the stability of the conjugate base (carboxylate ion).Electron-withdrawing groups ($-I$ effect) stabili

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$III > II > I$

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(B) The acidity of carboxylic acids depends on the stability of the conjugate base (carboxylate ion).Electron-withdrawing groups ($-I$ effect) stabilize the conjugate base and increase acidity.The hybridization of the carbon atom attached to the carboxyl group determines the $-I$ effect strength: $sp > sp^2 > sp^3$.In $(III)$,the carbon is $sp$ hybridized (strongest $-I$ effect).In $(II)$,the carbon is $sp^2$ hybridized.In $(I)$,the carbon is $sp^3$ hybridized (weakest $-I$ effect).Therefore,the decreasing order of acidity is $III > II > I$.

Arrange the following acids in decreasing order of acidity:
$(I) CH_3CH_2COOH$
$(II) CH_2 = CH - COOH$
$(III) HC \equiv C - COOH$

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Arrange the following acids in decreasing order of acidity:$(I) CH_3CH_2COOH$$(II) CH_2 = CH - COOH$$(III) HC \equiv C - COOH$