Find the number of optical isomers for the co | vedclass

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(D) The given compound is an aldohexose (specifically glucose or its stereoisomers) with the structure $CHO-(CHOH)_4-CH_2OH$. There are $n = 4$ chiral

Vedclass · Accepted Answer

$16$

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(D) The given compound is an aldohexose (specifically glucose or its stereoisomers) with the structure $CHO-(CHOH)_4-CH_2OH$. There are $n = 4$ chiral carbon atoms in this molecule. The number of optically active isomers $(a)$ is given by $2^n = 2^4 = 16$. Since the molecule is asymmetric (the two ends are different,$CHO$ and $CH_2OH$),there are no meso compounds $(m = 0)$. Therefore,the total number of optical isomers is $2^n = 16$.

Find the number of optical isomers for the compound $CHO-CH(OH)-CH(OH)-CH(OH)-CH(OH)-CH_2OH$.

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