Give the IUPAC name of the compound H-Cequiv | vedclass

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(A) $1$. Identify the longest carbon chain containing both the double and triple bonds. The chain has $5$ carbon atoms,so the parent name is 'pent'.$2

Vedclass · Accepted Answer

Pent-$1$-en-$4$-yne

Vedclass · Answer

(A) $1$. Identify the longest carbon chain containing both the double and triple bonds. The chain has $5$ carbon atoms,so the parent name is 'pent'.$2$. Number the chain starting from the end that gives the lowest locants to the multiple bonds. Numbering from the left gives the triple bond at $C-1$ and the double bond at $C-4$. Numbering from the right gives the double bond at $C-1$ and the triple bond at $C-4$.$3$. According to $IUPAC$ rules,if there is a choice between a double and a triple bond,the double bond is given priority for the lower number. Thus,we number from the right: $CH_2=CH-CH_2-C\equiv CH$.$4$. The double bond is at $C-1$ and the triple bond is at $C-4$. The name is Pent-$1$-en-$4$-yne.

Give the $IUPAC$ name of the compound $H-C\equiv C-CH_2-CH=CH_2$.

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