What is the absolute configuration of the giv | vedclass

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(A) To determine the absolute configuration,we assign priorities to the groups attached to each chiral center using Cahn-Ingold-Prelog $(CIP)$ rules.F

Vedclass · Accepted Answer

$2S, 3R$

Vedclass · Answer

(A) To determine the absolute configuration,we assign priorities to the groups attached to each chiral center using Cahn-Ingold-Prelog $(CIP)$ rules.For $C-2$:$1$. $-Cl$ (Priority $1$)$2$. $-CH(Cl)C_2H_5$ (Priority $2$)$3$. $-CH_3$ (Priority $3$)$4$. $-H$ (Priority $4$)The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise,but since the lowest priority group $(-H)$ is on a horizontal bond,the configuration is inverted. Thus,$C-2$ is $S$.For $C-3$:$1$. $-Cl$ (Priority $1$)$2$. $-CH(Cl)CH_3$ (Priority $2$)$3$. $-C_2H_5$ (Priority $3$)$4$. $-H$ (Priority $4$)The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is counter-clockwise,but since the lowest priority group $(-H)$ is on a horizontal bond,the configuration is inverted. Thus,$C-3$ is $R$.Therefore,the configuration is $2S, 3R$.

$A$. Acetaldehyde,vinyl alcohol	$1$. Enantiomers
$B$. Eclipsed and staggered ethane	$2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol	$3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine	$4$. Conformational isomers
	$5$. Metamers

What is the absolute configuration of the given compound?

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Match the following:
$A$. Acetaldehyde,vinyl alcohol $1$. Enantiomers
$B$. Eclipsed and staggered ethane $2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol $3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine $4$. Conformational isomers
$5$. Metamers

The compound $C_{4}H_{10}O$ can show which of the following types of isomerism?

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