According to the CIP sequence rule,which of t | vedclass

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(B) To determine priority using the $CIP$ (Cahn-Ingold-Prelog) rules,we look at the atomic number of the atom directly attached to the chiral center.$

Vedclass · Accepted Answer

$-OH > -COOH > -CHO > -CH_2OH$

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(B) To determine priority using the $CIP$ (Cahn-Ingold-Prelog) rules,we look at the atomic number of the atom directly attached to the chiral center.$1$. The atoms attached are $O$ (in $-OH$),$C$ (in $-COOH$),$C$ (in $-CHO$),and $C$ (in $-CH_2OH$).$2$. Since $O$ has a higher atomic number $(8)$ than $C$ $(6)$,$-OH$ has the highest priority $(1)$.$3$. Now compare the carbon-containing groups: $-COOH$,$-CHO$,and $-CH_2OH$.$4$. In $-COOH$,$C$ is bonded to $(O, O, O)$. In $-CHO$,$C$ is bonded to $(O, O, H)$. In $-CH_2OH$,$C$ is bonded to $(O, H, H)$.$5$. Comparing the first point of difference: $(O, O, O) > (O, O, H) > (O, H, H)$.$6$. Thus,the priority order is $-OH > -COOH > -CHO > -CH_2OH$.

According to the $CIP$ sequence rule,which of the following is the correct order of decreasing priority?

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