Write the IUPAC name of the compound: H_3C-C( | vedclass

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(D) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority,so the parent chain is a pentanoic acid

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$3-$hydroxy$-2-$nitro$-4-$oxopentanoic acid

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(D) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority,so the parent chain is a pentanoic acid derivative.$2$. Number the chain starting from the carbon of the $-COOH$ group as $C-1$.$3$. Identify substituents and their positions: The $-NO_2$ group is at $C-2$,the $-OH$ group is at $C-3$,and the ketone group $(=O)$ is at $C-4$.$4$. Arrange substituents alphabetically: $H$ (hydroxy) comes before $N$ (nitro).$5$. The name is $3-$hydroxy$-2-$nitro$-4-$oxopentanoic acid.

Write the $IUPAC$ name of the compound: $H_3C-C(=O)-CH(OH)-CH(NO_2)-CO_2H$

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The order of priority of the following functional groups in the $IUPAC$ method of naming organic compounds is:
$(i) >C=O$
$(ii) -NH_2$
$(iii) -CN$
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The $IUPAC$ name of $CH_3-CH(OCH_3)-CHO$ is

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