Which of the following compounds exists as ge | vedclass

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(B) For a compound to exhibit geometric isomerism,each carbon atom of the double bond must be attached to two different groups. $2-$pentene has the st

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$2-$pentene

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(B) For a compound to exhibit geometric isomerism,each carbon atom of the double bond must be attached to two different groups. $2-$pentene has the structure $CH_3-CH=CH-CH_2-CH_3$. In this molecule,the first carbon of the double bond is attached to a $-H$ and a $-CH_3$ group,and the second carbon is attached to a $-H$ and a $-CH_2CH_3$ group. Since both carbons have different groups attached,it can exist as $cis$ and $trans$ isomers. $2-$pentyne is an alkyne,$2-$methylpropene has two identical $-CH_3$ groups on one carbon,and $2-$methyl$-2-$butene also has two identical $-CH_3$ groups on one carbon,so they do not show geometric isomerism.

Which of the following compounds exists as geometric isomers?

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