Which of the following molecules exhibit conf | vedclass

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(A) Conformational isomerism arises due to rotation around a single bond. For a molecule to exhibit conformational isomerism,it must have at least thr

Vedclass · Accepted Answer

$2, 4, 5, 6$

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(A) Conformational isomerism arises due to rotation around a single bond. For a molecule to exhibit conformational isomerism,it must have at least three consecutive single bonds (sigma bonds) to allow for rotation around the central bond.$(1)$ $CH_4$: No central bond for rotation.$(2)$ $CH_3OH$: Rotation around $C-O$ bond is possible,but it is generally not considered to exhibit distinct conformational isomers due to the symmetry of the methyl group.$(3)$ $H_2O$: No central bond for rotation.$(4)$ $H_2O_2$ $(H-O-O-H)$: Has three consecutive bonds ($H-O$,$O-O$,$O-H$),allowing rotation around the $O-O$ bond.$(5)$ $C_2H_6$ $(CH_3-CH_3)$: Has three consecutive bonds ($H-C$,$C-C$,$C-H$),allowing rotation around the $C-C$ bond.$(6)$ $C_3H_8$ $(CH_3-CH_2-CH_3)$: Has multiple consecutive bonds,allowing rotation around $C-C$ bonds.Thus,molecules $(2), (4), (5),$ and $(6)$ exhibit conformational isomerism.

Which of the following molecules exhibit conformational isomerism?

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