Which of the following compounds exhibits opt | vedclass

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(D) For a compound to exhibit optical isomerism,it must contain at least one chiral carbon atom (a carbon atom bonded to four different groups).$1$. $

Vedclass · Accepted Answer

$2$-methylbutanoic acid

Vedclass · Answer

(D) For a compound to exhibit optical isomerism,it must contain at least one chiral carbon atom (a carbon atom bonded to four different groups).$1$. $2$-methylbut$-1$-ene: $CH_2=C(CH_3)CH_2CH_3$. No chiral carbon.$2$. $3$-methylbut$-1$-ene: $CH_2=CHCH(CH_3)CH_3$. No chiral carbon.$3$. $3$-methylbutanoic acid: $(CH_3)_2CHCH_2COOH$. No chiral carbon.$4$. $2$-methylbutanoic acid: $CH_3CH_2CH(CH_3)COOH$. The carbon at position $2$ is bonded to $-H$,$-CH_3$,$-CH_2CH_3$,and $-COOH$ groups. Since all four groups are different,this carbon is chiral. Thus,it exhibits optical isomerism.

Which of the following compounds exhibits optical isomerism?

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