The number of geometric isomers for [Pt(NH_3) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The complex $[Pt(NH_3)_2Cl_2]$ is a square planar complex of the type $[MA_2B_2]$.It exhibits geometric isomerism due to the different spatial arr

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) The complex $[Pt(NH_3)_2Cl_2]$ is a square planar complex of the type $[MA_2B_2]$.It exhibits geometric isomerism due to the different spatial arrangements of the ligands around the central metal atom.The two geometric isomers are:$1$. $cis$-isomer: In this isomer,the two identical ligands ($NH_3$ or $Cl$) are adjacent to each other.$2$. $trans$-isomer: In this isomer,the two identical ligands ($NH_3$ or $Cl$) are opposite to each other.Thus,there are $2$ geometric isomers.

The number of geometric isomers for $[Pt(NH_3)_2Cl_2]$ is .......

Similar Questions

Identify the pair of complexes that have the same magnetic moment (spin-only value).

How many geometrical isomers are shown by the complex $[Pt(NH_3)(NH_2OH)(H_2O)(Py)]^+$?

The number of possible geometric isomers for a square planar complex $[Mabcd]$ is ............. ($M =$ central metal,$a, b, c, d =$ monodentate ligands).

$Ni(CO)_4$ and $[Ni(NH_3)_4]^{2+}$ do not differ in

The spin-only magnetic moment in $BM$ of $[Fe(CO)_4(C_2O_4)]^+$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module