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(D) The total number of chlorine atoms in the complex is $4$. Since $1/4$ of the chlorine is precipitated by $AgNO_3$,it means $4 	imes (1/4) = 1$ ch

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$PtCl_4 \cdot 3H_2O$

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(D) The total number of chlorine atoms in the complex is $4$. Since $1/4$ of the chlorine is precipitated by $AgNO_3$,it means $4 	imes (1/4) = 1$ chlorine atom is present as a free chloride ion $(Cl^-)$ outside the coordination sphere. The formula must be of the form $[Pt(H_2O)_xCl_3]Cl$. Among the given options,$PtCl_4 \cdot 3H_2O$ can be written as $[Pt(H_2O)_3Cl_3]Cl$,which provides $1$ mole of $Cl^-$ ions per mole of the complex. Therefore,the correct formula is $PtCl_4 \cdot 3H_2O$.

When $AgNO_3$ is added to an aqueous solution of a platinum complex,$1/4$ of the total chlorine content is precipitated. Determine the formula of the platinum complex from the given options.

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