Which of the following ions has the highest m | vedclass

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(B) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each complex:$1$. $[Cr(H_2O)_6]^{3+}$: $Cr^{3+}$ is $3d^3$

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$[Fe(H_2O)_6]^{2+}$

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(B) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each complex:$1$. $[Cr(H_2O)_6]^{3+}$: $Cr^{3+}$ is $3d^3$. Number of unpaired electrons $(n)$ = $3$.$2$. $[Fe(H_2O)_6]^{2+}$: $Fe^{2+}$ is $3d^6$. With $H_2O$ as a weak field ligand,$n = 4$.$3$. $[Cu(H_2O)_6]^{2+}$: $Cu^{2+}$ is $3d^9$. Number of unpaired electrons $(n)$ = $1$.$4$. $[Zn(H_2O)_6]^{2+}$: $Zn^{2+}$ is $3d^{10}$. Number of unpaired electrons $(n)$ = $0$.Since the magnetic moment $\mu = \sqrt{n(n+2)} \ BM$,the complex with the highest number of unpaired electrons will have the highest magnetic moment.Thus,$[Fe(H_2O)_6]^{2+}$ with $n = 4$ has the highest magnetic moment.

Complex	Structure and magnetic property
$i$. $NiCl_4^{2-}$	$p$. tetrahedral and diamagnetic
$ii$. $Ni(CO)_4$	$q$. tetrahedral and paramagnetic
$iii$. $PtCl_4^{2-}$	$r$. square planar and diamagnetic
$iv$. $Ni(CN)_4^{2-}$	$s$. square planar and paramagnetic

Which of the following ions has the highest magnetic moment?

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