The theoretical value of the magnetic moment | vedclass

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(B) In $[Ni(Cl)_4]^{2-}$,the oxidation state of $Ni$ is $+2$.The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.According to crystal field theor

Vedclass · Accepted Answer

$2.83$

Vedclass · Answer

(B) In $[Ni(Cl)_4]^{2-}$,the oxidation state of $Ni$ is $+2$.The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.According to crystal field theory,$Cl^-$ is a weak field ligand,so no pairing of electrons occurs in the $3d$ orbitals.There are $2$ unpaired electrons in the $3d$ orbitals.The magnetic moment $\mu$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.$\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \ B.M.$

The theoretical value of the magnetic moment of the complex ion $[Ni(Cl)_4]^{2-}$ is .......... $B.M.$

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