The magnetic moment of [NiCl_4]^{2-} is .... | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In $[NiCl_4]^{2-}$,the oxidation state of $Ni$ is $+2$. The atomic number of $Ni$ is $28$,so the electronic configuration of $Ni^{2+}$ is $[Ar] 3d

Vedclass · Accepted Answer

$2.82$

Vedclass · Answer

(C) In $[NiCl_4]^{2-}$,the oxidation state of $Ni$ is $+2$. The atomic number of $Ni$ is $28$,so the electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$. $Cl^-$ is a weak field ligand,so it does not cause pairing of electrons in the $3d$ orbitals. Thus,there are $2$ unpaired electrons in the $3d$ orbitals. The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons. Substituting $n = 2$,we get $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.82 \ B.M.$

The magnetic moment of $[NiCl_4]^{2-}$ is .... $B.M.$ (spin-only).

Similar Questions

$Cis-trans$ isomerism is found in square planar complexes of the molecular formula: ($A$ and $B$ are monodentate ligands):

The spin only magnetic moment value (in Bohr magneton units) of $Cr(CO)_6$ is

The value of 'spin only' magnetic moment for one of the following configurations is $2.84 \ BM$. The correct one is:

The complexes $[Co(NH_3)_5Br]SO_4$ and $[Co(NH_3)_5SO_4]Br$ are examples of which type of isomerism?

If $n$ is the number of unpaired electrons,then the magnetic moment $(B.M.)$ of a transition metal/ion is given by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module