Which statement is incorrect?

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(A) For $Ni(CO)_4$,the oxidation state of $Ni$ is $0$. The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. In the presence of a strong field lig

Vedclass · Accepted Answer

$Ni(CO)_4$ $-$ Tetrahedral,Paramagnetic

Vedclass · Answer

(A) For $Ni(CO)_4$,the oxidation state of $Ni$ is $0$. The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. In the presence of a strong field ligand like $CO$,the $4s$ electrons pair up into the $3d$ orbital,resulting in $sp^3$ hybridization. Since all electrons are paired,$Ni(CO)_4$ is tetrahedral and diamagnetic. Therefore,the statement '$Ni(CO)_4$ $-$ Tetrahedral,Paramagnetic' is incorrect.

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