The Effective Atomic Number (EAN) of Ni in Ni | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The formula for Effective Atomic Number $(EAN)$ is: $EAN = Z - 	ext{oxidation state} + 2 	imes 	ext{coordination number}$.For $Ni(CO)_4$:$Z$ (a

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(D) The formula for Effective Atomic Number $(EAN)$ is: $EAN = Z - 	ext{oxidation state} + 2 	imes 	ext{coordination number}$.For $Ni(CO)_4$:$Z$ (atomic number of $Ni$) = $28$.Oxidation state of $Ni$ = $0$ (since $CO$ is a neutral ligand).Coordination number = $4$.$EAN = 28 - 0 + 2 	imes 4 = 28 + 8 = 36$.

The Effective Atomic Number $(EAN)$ of $Ni$ in $Ni(CO)_4$ is:

Similar Questions

Which of the following follows the $EAN$ rule?

The effective atomic number of $[A(NH_3)_6]Cl_3$ is $33$. What is the atomic number of element $A$?

Which of the following complexes does not follow the $EAN$ rule?

Which of the following species can act as a reducing agent?

Effective Atomic Number $(EAN)$ of $Co$ in $Co_2(CO)_8$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module