Write the correct order of wavelength of abso | vedclass

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Question

(A) The wavelength of absorption $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.$\lambda \propto \frac{1}{\D

Vedclass · Accepted Answer

$[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$

Vedclass · Answer

(A) The wavelength of absorption $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.$\lambda \propto \frac{1}{\Delta_o}$.According to the spectrochemical series,the strength of ligands is $H_2O Therefore,the crystal field splitting energy follows the order: $[Ni(H_2O)_6]^{2+} Consequently,the wavelength of absorption follows the reverse order: $[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$.

$I$	$II$
$(a). [Cr(H_2O)_6]^{2+}$	$[Cr(H_2O)_6]^{3+}$
$(b). [Fe(H_2O)_6]^{3+}$	$[Fe(CN)_6]^{3-}$
$(c). [Fe(CN)_6]^{3-}$	$[Ru(CN)_6]^{3-}$
$(d). [NiF_6]^{4-}$	$[NiF_6]^{2-}$

Write the correct order of wavelength of absorption in the visible region for the following complexes:

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