One mole of the coordination compound Co(NH_3 | vedclass

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(D) The complex $Co(NH_3)_5Cl_3$ reacts with $2$ moles of $AgNO_3$ to form $2$ moles of $AgCl(s)$,which indicates that there are $2$ chloride ions out

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$[Co(NH_3)_5Cl]Cl_2$

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(D) The complex $Co(NH_3)_5Cl_3$ reacts with $2$ moles of $AgNO_3$ to form $2$ moles of $AgCl(s)$,which indicates that there are $2$ chloride ions outside the coordination sphere. Thus,the formula is $[Co(NH_3)_5Cl]Cl_2$. Upon dissolution,it ionizes as: $[Co(NH_3)_5Cl]Cl_2 \rightarrow [Co(NH_3)_5Cl]^{2+} + 2Cl^-$. This gives a total of $1 + 2 = 3$ moles of ions,which matches the given information.

One mole of the coordination compound $Co(NH_3)_5Cl_3$ gives $3$ moles of ions upon dissolution in water. Furthermore,one mole of this complex reacts with $2$ moles of $AgNO_3$ solution to produce $2$ moles of $AgCl(s)$. The structure of the complex is:

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