Which of the following has a square planar ge | vedclass

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(D) To determine the geometry,we look at the central metal ion and the nature of the ligand.$1$. $[CoCl_4]^{2-}$: $Co^{2+}$ is $d^7$,$Cl^-$ is a weak

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$[PtCl_4]^{2-}$

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(D) To determine the geometry,we look at the central metal ion and the nature of the ligand.$1$. $[CoCl_4]^{2-}$: $Co^{2+}$ is $d^7$,$Cl^-$ is a weak field ligand,resulting in $sp^3$ hybridization (tetrahedral).$2$. $[FeCl_4]^{2-}$: $Fe^{2+}$ is $d^6$,$Cl^-$ is a weak field ligand,resulting in $sp^3$ hybridization (tetrahedral).$3$. $[NiCl_4]^{2-}$: $Ni^{2+}$ is $d^8$,$Cl^-$ is a weak field ligand,resulting in $sp^3$ hybridization (tetrahedral).$4$. $[PtCl_4]^{2-}$: $Pt^{2+}$ is a $5d$ series metal. For $5d$ series metals,even weak field ligands like $Cl^-$ cause pairing of electrons due to high crystal field splitting energy,resulting in $dsp^2$ hybridization,which corresponds to square planar geometry.

Which of the following has a square planar geometry? $(Co = 27, Ni = 28, Fe = 26, Pt = 78)$

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