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(A) The complex ion $[CO(NH_3)_4Cl_2]^{+}$ is of the type $[MA_4B_2]^n+$.This type of octahedral complex exhibits geometrical isomerism.The two possib

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$2$

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(A) The complex ion $[CO(NH_3)_4Cl_2]^{+}$ is of the type $[MA_4B_2]^n+$.This type of octahedral complex exhibits geometrical isomerism.The two possible geometrical isomers are:$1$. $cis$-isomer: In this form,the two $Cl^-$ ligands are adjacent to each other (at $90^\circ$ angle).$2$. $trans$-isomer: In this form,the two $Cl^-$ ligands are opposite to each other (at $180^\circ$ angle).Since both isomers are achiral (they possess a plane of symmetry),they do not exhibit optical isomerism.Therefore,the total number of possible isomeric forms is $2$.

How many isomeric forms are possible for the ion $[CO(NH_3)_4Cl_2]^{+}$?

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