How many geometrical isomers are possible for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a square planar complex of the type $[M(abcd)]$,where $a, b, c, d$ are four different ligands,the number of geometrical isomers is $3$.In this

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) For a square planar complex of the type $[M(abcd)]$,where $a, b, c, d$ are four different ligands,the number of geometrical isomers is $3$.In this case,the complex is $[Pt(NH_3)(Br)(Cl)(Py)]^{2+}$.We can fix one ligand (e.g.,$NH_3$) at one position and then arrange the other three ligands $(Br, Cl, Py)$ in the remaining three positions.$1$. $NH_3$ trans to $Br$ (with $Cl$ and $Py$ trans to each other).$2$. $NH_3$ trans to $Cl$ (with $Br$ and $Py$ trans to each other).$3$. $NH_3$ trans to $Py$ (with $Br$ and $Cl$ trans to each other).Thus,there are $3$ possible geometrical isomers.

How many geometrical isomers are possible for the square planar complex $[Pt(NH_3)(Br)(Cl)(Py)]^{2+}$?

Similar Questions

$[Co(NH_3)_5NO_2]Cl_2$ and $[Co(NH_3)_5(ONO)]Cl_2$ are related to each other as

Correct increasing order of spin magnetic moment $($in $B.M.)$ for the following complexes is:
$(I) \ [FeF_6]^{3-} \ (II) \ [V(H_2O)_6]^{2+} \ (III) \ [Fe(H_2O)_6]^{2+}$

$[Fe(NO_2)_3Cl_3]$ and $[Fe(ONO)_3Cl_3]$ show:

Which of the following polymerisation isomers of the compound having empirical formula $Cr(NH_3)_3(NO_2)_3$ has the lowest molecular mass?

Select the correct statement$(s)$ regarding the $[Ni(DMG)_2]$ complex compound.

Vedclass Test Series

Exam Paper Generator

Online Exam Module