The oxidation state of chromium in the dimeri | vedclass

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Question

(C) Let the oxidation state of $Cr$ be $x$.In the complex $[(H_2O)_4Cr(OH)_2Cr(H_2O)_4]^{4+}$,the ligands are $H_2O$ (neutral,charge $= 0$) and $OH^-$

Vedclass · Accepted Answer

$+3$

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(C) Let the oxidation state of $Cr$ be $x$.In the complex $[(H_2O)_4Cr(OH)_2Cr(H_2O)_4]^{4+}$,the ligands are $H_2O$ (neutral,charge $= 0$) and $OH^-$ (charge $= -1$).The total charge of the complex is $+4$.Applying the oxidation state rule:$2x + 8(0) + 2(-1) = +4$$2x - 2 = +4$$2x = 6$$x = +3$Therefore,the oxidation state of chromium is $+3$.

The oxidation state of chromium in the dimeric hydroxo-bridged complex $[(H_2O)_4Cr(OH)_2Cr(H_2O)_4]^{4+}$ is:

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