Which of the following statements is incorrec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. $[Cu(NH_3)_4]^{2+}$ is square planar due to $dsp^2$ hybridization.$2$. $Ni(CO)_4$ contains $CO$ which is a neutral ligand.$3$. In $[Fe(CN)_6]

Vedclass · Accepted Answer

$[Fe(CN)_6]^{3-}$ - $sp^3d^2$

Vedclass · Answer

(C) $1$. $[Cu(NH_3)_4]^{2+}$ is square planar due to $dsp^2$ hybridization.$2$. $Ni(CO)_4$ contains $CO$ which is a neutral ligand.$3$. In $[Fe(CN)_6]^{3-}$,$Fe$ is in $+3$ oxidation state $(3d^5)$. Since $CN^-$ is a strong field ligand,it causes pairing,resulting in $d^2sp^3$ hybridization (inner orbital complex),not $sp^3d^2$.$4$. For $[Co(en)_3]^{3+}$,$EAN = Z - 	ext{oxidation state} + 2 	imes 	ext{coordination number} = 27 - 3 + 2(6) = 24 + 12 = 36$,which is the atomic number of $Kr$. Thus,it follows the $EAN$ rule.

Which of the following statements is incorrect?

Similar Questions

Which of the following statements is incorrect?

Which complex compound possesses $sp^3d^2$ hybridisation?

Which of the following complexes does not involve inner orbital hybridization?

If $Hund's$ rule is violated,then select the $CORRECT$ statement regarding $[Ni(NH_3)_6]^{2+}$:

$[Co(C_2O_4)_3]^{3-}$ is a :

Vedclass Test Series

Exam Paper Generator

Online Exam Module