The equation of the x-axis is ..... | vedclass

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(C) The $x$-axis passes through the origin $(0, 0, 0)$.Its direction ratios are $(1, 0, 0)$ because it is parallel to the vector $\vec{i}$.The symmetr

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$\frac{x}{1} = \frac{y}{0} = \frac{z}{0}$

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(C) The $x$-axis passes through the origin $(0, 0, 0)$.Its direction ratios are $(1, 0, 0)$ because it is parallel to the vector $\vec{i}$.The symmetric form of the equation of a line passing through $(x_1, y_1, z_1)$ with direction ratios $(a, b, c)$ is $\frac{x - x_1}{a} = \frac{y - y_1}{b} = \frac{z - z_1}{c}$.Substituting $(x_1, y_1, z_1) = (0, 0, 0)$ and $(a, b, c) = (1, 0, 0)$,we get $\frac{x - 0}{1} = \frac{y - 0}{0} = \frac{z - 0}{0}$.Thus,the equation is $\frac{x}{1} = \frac{y}{0} = \frac{z}{0}$.

$(a)$ Clostridium butylicum	$(i)$ Cyclosporin-$A$
$(b)$ Trichoderma polysporum	$(ii)$ Butyric acid
$(c)$ Monascus purpureus	$(iii)$ Citric acid
$(d)$ Aspergillus niger	$(iv)$ Blood cholesterol lowering agent

The equation of the $x$-axis is .....

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