The equation of the line passing through $(1, -2)$ and perpendicular to the $y$-axis is:

Find the equations of the lines parallel to the axes and passing through the point $(-2, 3)$.

Reduce the following equation into intercept form and find its intercepts on the axes: $4x - 3y = 6$.

Find the equation of the line whose perpendicular distance from the origin is $4$ units and the angle which the normal makes with the positive direction of the $x$-axis is $15^{\circ}$.

If the line $y = mx + c$ passes through the points $(2, 4)$ and $(3, -5)$,then:

$A$ line passes through $(2,2)$ and is perpendicular to the line $3x+y=3$. Its $y$-intercept is