Find the y-intercept of a line that is perpen | vedclass

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(D) The given line is $3x + y = 3$,which can be written as $y = -3x + 3$. The slope of this line is $m_1 = -3$.Since the required line is perpendicula

Vedclass · Accepted Answer

$4/3$

Vedclass · Answer

(D) The given line is $3x + y = 3$,which can be written as $y = -3x + 3$. The slope of this line is $m_1 = -3$.Since the required line is perpendicular to the given line,its slope $m_2$ must satisfy $m_1 	imes m_2 = -1$.Thus,$-3 	imes m_2 = -1$,which gives $m_2 = 1/3$.The equation of the line passing through $(2, 2)$ with slope $m_2 = 1/3$ is given by $y - y_1 = m_2(x - x_1)$.Substituting the values: $y - 2 = \frac{1}{3}(x - 2)$.Multiplying by $3$: $3y - 6 = x - 2$,which simplifies to $x - 3y + 4 = 0$.To find the $y$-intercept,set $x = 0$: $0 - 3y + 4 = 0$,which gives $3y = 4$,so $y = 4/3$.Therefore,the $y$-intercept is $4/3$.

Find the $y$-intercept of a line that is perpendicular to $3x + y = 3$ and passes through the point $(2, 2)$.

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