If the point (5, 2) divides the segment of th | vedclass

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(B) Let the line be $\frac{x}{a} + \frac{y}{b} = 1$. The intercepts on the axes are $(a, 0)$ and $(0, b)$.Since the point $(5, 2)$ is the midpoint of

Vedclass · Accepted Answer

$2x + 5y = 20$

Vedclass · Answer

(B) Let the line be $\frac{x}{a} + \frac{y}{b} = 1$. The intercepts on the axes are $(a, 0)$ and $(0, b)$.Since the point $(5, 2)$ is the midpoint of the segment between the axes,we have:$\frac{a+0}{2} = 5 \Rightarrow a = 10$$\frac{0+b}{2} = 2 \Rightarrow b = 4$Substituting these values into the intercept form equation:$\frac{x}{10} + \frac{y}{4} = 1$Multiplying by $20$ to clear the denominators:$2x + 5y = 20$

If the point $(5, 2)$ divides the segment of the line between the axes into two equal parts,then its equation is:

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