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(B) The vertex of the parabola is $V(0, a)$ and the focus is $S(0, 0)$.Since the focus and vertex lie on the $y$-axis,the axis of the parabola is the

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$x^2 = 4a(a - y)$

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(B) The vertex of the parabola is $V(0, a)$ and the focus is $S(0, 0)$.Since the focus and vertex lie on the $y$-axis,the axis of the parabola is the $y$-axis.The distance between the vertex and the focus is $a = |a - 0| = |a|$.Since the focus is below the vertex,the parabola opens downwards.The standard form for a downward-opening parabola with vertex $(h, k)$ is $(x - h)^2 = -4a(y - k)$.Here,$(h, k) = (0, a)$ and the distance from vertex to focus is $a$.Substituting these values,we get $(x - 0)^2 = -4a(y - a)$.$x^2 = -4a(y - a)$.$x^2 = 4a(a - y)$.

If the vertex of a parabola is $(0, a)$ and the focus is $(0, 0)$,what is its equation?

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