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(C) The given equation is $x^2 + 2xy - y^2 = 0$.Comparing this with the general equation of a pair of lines $ax^2 + 2hxy + by^2 = 0$,we get $a = 1$,$h

Vedclass · Accepted Answer

$\pi /2$

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(C) The given equation is $x^2 + 2xy - y^2 = 0$.Comparing this with the general equation of a pair of lines $ax^2 + 2hxy + by^2 = 0$,we get $a = 1$,$h = 1$,and $b = -1$.The angle $	heta$ between the pair of lines is given by $	an 	heta = \left| \frac{2\sqrt{h^2 - ab}}{a + b} ight|$.Since $a + b = 1 + (-1) = 0$,the denominator is $0$.When the denominator is $0$,$	an 	heta$ is undefined,which implies $	heta = \pi / 2$.Alternatively,if $a + b = 0$,the lines are perpendicular to each other.

The angle between the pair of lines represented by $x^2 + 2xy - y^2 = 0$ is:

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