What are the coordinates of the point that di | vedclass

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(C) The formula for external division of a line segment joining points $(x_1, y_1)$ and $(x_2, y_2)$ in the ratio $m : n$ is given by: $P = (\frac{mx_

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$(-41/2, 69/2)$

Vedclass · Answer

(C) The formula for external division of a line segment joining points $(x_1, y_1)$ and $(x_2, y_2)$ in the ratio $m : n$ is given by: $P = (\frac{mx_2 - nx_1}{m - n}, \frac{my_2 - ny_1}{m - n})$ Given points are $(x_1, y_1) = (-3, -4)$ and $(x_2, y_2) = (-8, 7)$ with ratio $m : n = 7 : 5$. Substituting the values: $x = \frac{7(-8) - 5(-3)}{7 - 5} = \frac{-56 + 15}{2} = \frac{-41}{2}$ $y = \frac{7(7) - 5(-4)}{7 - 5} = \frac{49 + 20}{2} = \frac{69}{2}$ Thus,the coordinates are $(-41/2, 69/2)$.

What are the coordinates of the point that divides the line segment joining the points $(-3, -4)$ and $(-8, 7)$ externally in the ratio $7 : 5$?

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