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(B) The range of a projectile fired with velocity $u$ at an angle $	heta$ is given by $R = \frac{u^2 \sin(2	heta)}{g}$.For a fixed velocity $u$,the

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$\pi \frac{u^4}{g^2}$

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(B) The range of a projectile fired with velocity $u$ at an angle $	heta$ is given by $R = \frac{u^2 \sin(2	heta)}{g}$.For a fixed velocity $u$,the maximum horizontal range $R_{\max}$ is achieved when $	heta = 45^\circ$,which is $R_{\max} = \frac{u^2}{g}$.Since bullets are fired in all directions,they cover a circular area on the ground with radius $r = R_{\max} = \frac{u^2}{g}$.The area $A$ covered is given by $A = \pi r^2$.Substituting the value of $r$,we get $A = \pi \left( \frac{u^2}{g} ight)^2 = \pi \frac{u^4}{g^2}$.

Bullets are fired in all directions with the same velocity $u$. What is the maximum area covered by them?

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