(D) Given: Radius $r = 0.20 \ m$,initial angular velocity $\omega_0 = 0$,angular acceleration $\alpha = 1 \ rad/s^2$,and angular displacement $\theta

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(D) Given: Radius $r = 0.20 \ m$,initial angular velocity $\omega_0 = 0$,angular acceleration $\alpha = 1 \ rad/s^2$,and angular displacement $\theta = 90^o = \pi/2 \ rad$.Using the kinematic equation for rotation: $\omega^2 = \omega_0^2 + 2\alpha\theta$.Substituting the values: $\omega^2 = 0^2 + 2 \times 1 \times (\pi/2) = \pi \ rad^2/s^2$.The centripetal acceleration $a_c$ is given by $a_c = \omega^2 r$.Substituting the values: $a_c = \pi \times 0.20 = 0.2 \ \pi \ m/s^2$.

Class 11 Physics 3-2.Motion in Plane Kinematics Circular Motion (Uniform Angular Accelaration)

Medium

$A$ wheel of radius $0.20 \ m$ starts from rest and rotates with an angular acceleration of $1 \ rad/s^2$. What will be the centripetal acceleration of a point on its circumference when it has rotated through an angle of $90^o$?

A
$\pi \ m/s^2$
B
$0.5 \ \pi \ m/s^2$
C
$2.0 \ \pi \ m/s^2$
D
$0.2 \ \pi \ m/s^2$

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3-2.Motion in Plane

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Kinematics Circular Motion (Uniform Angular Accelaration)

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$A$ wheel of radius $0.20 \ m$ starts from rest and rotates with an angular acceleration of $1 \ rad/s^2$. What will be the centripetal acceleration of a point on its circumference when it has rotated through an angle of $90^o$?

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$A$ wheel is rotating at $900 \, r.p.m.$ about its axis. When the power is cut-off,it comes to rest in $1 \, minute$. The angular retardation in $rad/s^2$ is:

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