A car travels frac{1}{3} of the total distanc | vedclass

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(C) Let the total distance be $x$.Time taken for the first part of the journey $(d_1 = x/3)$ at speed $v_1 = 20 \, km/hr$ is $t_1 = \frac{x/3}{20} = \

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$36$

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(C) Let the total distance be $x$.Time taken for the first part of the journey $(d_1 = x/3)$ at speed $v_1 = 20 \, km/hr$ is $t_1 = \frac{x/3}{20} = \frac{x}{60} \, hr$.Time taken for the remaining part of the journey $(d_2 = 2x/3)$ at speed $v_2 = 60 \, km/hr$ is $t_2 = \frac{2x/3}{60} = \frac{2x}{180} = \frac{x}{90} \, hr$.Total time $T = t_1 + t_2 = \frac{x}{60} + \frac{x}{90} = \frac{3x + 2x}{180} = \frac{5x}{180} = \frac{x}{36} \, hr$.Average speed $v_{avg} = \frac{	ext{Total distance}}{	ext{Total time}} = \frac{x}{x/36} = 36 \, km/hr$.

$A$ car travels $\frac{1}{3}$ of the total distance on a straight road at a speed of $20 \, km/hr$ and the remaining distance at a speed of $60 \, km/hr$. What is the average speed of the car in $km/hr$?

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