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(B) In the first case,the wire is suspended from a rigid support with a weight $W$ at its free end. The tension in the wire is $T_1 = W$. The extensio

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$1.0$

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(B) In the first case,the wire is suspended from a rigid support with a weight $W$ at its free end. The tension in the wire is $T_1 = W$. The extension is given by $\Delta l_1 = \frac{T_1 L}{AY} = \frac{WL}{AY} = 1.0 \, mm$.In the second case,the wire is passed over a massless,frictionless pulley with a weight $W$ attached to each end. The tension in the wire throughout its length is $T_2 = W$. The extension in this case is $\Delta l_2 = \frac{T_2 L}{AY} = \frac{WL}{AY}$.Since $T_1 = T_2 = W$,the extension remains the same.Therefore,$\Delta l_2 = 1.0 \, mm$.

$A$ wire is suspended from a rigid support and a weight $W$ is attached to its free end,causing an extension of $1.0 \, mm$. If the same wire is passed over a pulley and a weight $W$ is attached to each of its two ends,what will be the extension in the wire in $mm$?

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