Which of the following wires has the maximum | vedclass

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(B) The elastic potential energy stored in a stretched wire is given by $U = \frac{1}{2} 	imes 	ext{stress} 	imes 	ext{strain} 	imes 	ext{Volume

Vedclass · Accepted Answer

$F = 15 \ N, A = 2 \ cm^2, s = 10^{-3}$

Vedclass · Answer

(B) The elastic potential energy stored in a stretched wire is given by $U = \frac{1}{2} 	imes 	ext{stress} 	imes 	ext{strain} 	imes 	ext{Volume}$.Since $	ext{stress} = \frac{F}{A}$ and $	ext{Volume} = A 	imes L$,where $L$ is the original length of the wire:$U = \frac{1}{2} 	imes \frac{F}{A} 	imes s 	imes (A 	imes L) = \frac{1}{2} 	imes F 	imes s 	imes L$.Assuming the length $L$ is the same for all wires:$A) \ U = \frac{1}{2} 	imes 10 	imes 10^{-3} 	imes L = 5 	imes 10^{-3} \ L$$B) \ U = \frac{1}{2} 	imes 15 	imes 10^{-3} 	imes L = 7.5 	imes 10^{-3} \ L$$C) \ U = \frac{1}{2} 	imes 10 	imes 10^{-4} 	imes L = 0.5 	imes 10^{-3} \ L$$D) \ U = \frac{1}{2} 	imes 5 	imes 10^{-3} 	imes L = 2.5 	imes 10^{-3} \ L$Comparing the coefficients,option $B$ has the maximum energy.

Which of the following wires has the maximum elastic potential energy?

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