$A$ car of mass $100 \, kg$ is moving with a velocity of $5 \, m/s$. The force required to stop it in $\frac{1}{10} \, s$ is . . . . . . $N$.

$A$ body of mass $1.5 \ kg$ is moving towards south with a uniform velocity of $8 \ ms^{-1}$. $A$ force of $6 \ N$ is applied to the body towards east. The displacement of the body $3 \ s$ after the application of the force is (in $m$)

State Newton's second law of motion.

The velocity $(v)$ of a particle (under a force $F$) depends on its distance $(x)$ from the origin (with $x > 0$) as $v \propto \frac{1}{\sqrt{x}}$. Find how the magnitude of the force $(F)$ on the particle depends on $x$.

Newton's second law gives the measure of

$A$ force of $5 \, N$ acts on a body of weight $9.8 \, N$. What is the acceleration produced in $m/s^2$?