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(A) The tension in a string over a pulley with masses $m_1$ and $m_2$ in a stationary frame is given by $T = \frac{2m_1m_2}{m_1 + m_2}g$.When the pull

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$\frac{4W_1W_2}{W_1 + W_2}$

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(A) The tension in a string over a pulley with masses $m_1$ and $m_2$ in a stationary frame is given by $T = \frac{2m_1m_2}{m_1 + m_2}g$.When the pulley is accelerated upwards with acceleration $a$,the effective acceleration due to gravity becomes $g_{eff} = g + a$.Given $a = g$,the effective acceleration is $g_{eff} = g + g = 2g$.Substituting this into the tension formula:$T = \frac{2m_1m_2}{m_1 + m_2}(2g) = \frac{4m_1m_2}{m_1 + m_2}g$.Since $W = mg$,we can write $m = W/g$.Substituting $m_1 = W_1/g$ and $m_2 = W_2/g$:$T = \frac{4(W_1/g)(W_2/g)}{(W_1/g + W_2/g)}g = \frac{4W_1W_2}{g(W_1 + W_2)}g = \frac{4W_1W_2}{W_1 + W_2}$.

Two weights $W_1$ and $W_2$ are tied to a massless string and passed over a pulley. If the pulley is accelerated upwards with an acceleration $g$,what will be the tension in the string?

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