The work done in increasing the size of a rectangular soap film from $10 \, cm \times 6 \, cm$ to $10 \, cm \times 11 \, cm$ is $3 \times 10^{-4} \, J$. The surface tension of the film is:

  • A
    $1.5 \times 10^{-2} \, N/m$
  • B
    $3.0 \times 10^{-2} \, N/m$
  • C
    $6.0 \times 10^{-2} \, N/m$
  • D
    $11.0 \times 10^{-2} \, N/m$

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