When a capillary tube is dipped vertically in water,the water rises to a height of $2.0 \, cm$. If the capillary tube is tilted at an angle of $60^\circ$ with the vertical,what will be the length of the water column in the capillary tube in $cm$?

$A$ capillary tube of radius $r$ is immersed in a liquid and the mass of the liquid which rises up in it is $M$. If the radius of the tube is doubled,then the mass of the liquid which will rise in the capillary tube will be ............

Water rises up to a height of $4 \,cm$ in a capillary tube. The lower end of the capillary tube is at a depth of $8 \,cm$ below the water level. The mouth pressure required to blow an air bubble at the lower end of the capillary will be '$X$' $cm$ of water,where $X$ is equal to

The ratio of surface tensions of mercury and water is given to be $7.5$ while the ratio of their densities is $13.6$. Their contact angles with glass are close to $135^o$ and $0^o$,respectively. It is observed that mercury gets depressed by an amount $h$ in a capillary tube of radius $r_1$,while water rises by the same amount $h$ in a capillary tube of radius $r_2$. The ratio $(r_1/r_2)$ is then close to:

Two parallel glass plates are dipped partly in a liquid of density $d$ while keeping them vertical. If the distance between the plates is $x$, the surface tension of the liquid is $T$, and the angle of contact is $\theta$, then the rise of the liquid between the plates due to capillarity will be:

$A$ $20 \ cm$ long capillary tube is dipped in water. The water rises up to $8 \ cm$. If the entire arrangement is put in a freely falling elevator,the length of the water column in the capillary will be ....... $cm$.