$A$ capillary tube of radius $R$ is dipped in water,and water rises to a height $H$. The mass of water in the capillary tube is $M$. If a capillary tube of half the radius is dipped in water,what will be the mass of the water in the capillary tube?

The correct curve between the height or depression $h$ of liquid in a capillary tube and its radius $r$ is

If water rises in a capillary tube up to $3 \, cm$,what is the diameter of the capillary tube? (Surface tension of water $T = 7.2 \times 10^{-2} \, N/m$,density $\rho = 10^3 \, kg/m^3$,$g = 10 \, m/s^2$)

Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary of radius $\frac{r}{5}$ will be:

Three liquids have the same surface tension and densities $\rho_1, \rho_2$,and $\rho_3$ $(\rho_1 > \rho_2 > \rho_3)$. In three identical capillaries,the rise of the liquid is the same. The corresponding angles of contact $\theta_1, \theta_2$,and $\theta_3$ are related as:

The radii of the two columns in a $U$ tube are $r_1$ and $r_2$. When a liquid of density $\rho$ (angle of contact is $0^o$) is filled in it,the level difference of liquid in the two arms is $h$. The surface tension of the liquid is ($g =$ acceleration due to gravity):