Brass and lead rods of length 80 cm are conn | vedclass

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(B) The change in length of a rod due to thermal expansion is given by $\Delta L = L \alpha \Delta T$.For the brass rod:$\Delta L_{brass} = L \alpha_{

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$0.8$

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(B) The change in length of a rod due to thermal expansion is given by $\Delta L = L \alpha \Delta T$.For the brass rod:$\Delta L_{brass} = L \alpha_{brass} \Delta T = 80 \ cm 	imes (18 	imes 10^{-6} \ ^{\circ}C^{-1}) 	imes (100^{\circ}C - 0^{\circ}C) = 80 	imes 18 	imes 10^{-4} \ cm = 0.144 \ cm = 1.44 \ mm$.For the lead rod:$\Delta L_{lead} = L \alpha_{lead} \Delta T = 80 \ cm 	imes (28 	imes 10^{-6} \ ^{\circ}C^{-1}) 	imes (100^{\circ}C - 0^{\circ}C) = 80 	imes 28 	imes 10^{-4} \ cm = 0.224 \ cm = 2.24 \ mm$.The difference in length between their ends is $\Delta L_{lead} - \Delta L_{brass} = 2.24 \ mm - 1.44 \ mm = 0.8 \ mm$.

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