When 300 , J of heat is given to a body of ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Mass $m = 25 \, g = 0.025 \, kg$,Heat $Q = 300 \, J$,Change in temperature $\Delta T = 45^{\circ}C - 25^{\circ}C = 20^{\circ}C$.Heat capaci

Vedclass · Accepted Answer

$15 \, J/^{\circ}C, 600 \, J/kg \cdot ^{\circ}C$

Vedclass · Answer

(A) Given: Mass $m = 25 \, g = 0.025 \, kg$,Heat $Q = 300 \, J$,Change in temperature $\Delta T = 45^{\circ}C - 25^{\circ}C = 20^{\circ}C$.Heat capacity $(C)$ is defined as $C = \frac{Q}{\Delta T} = \frac{300}{20} = 15 \, J/^{\circ}C$.Specific heat capacity $(c)$ is defined as $c = \frac{C}{m} = \frac{15}{0.025} = 600 \, J/kg \cdot ^{\circ}C$.Therefore,the heat capacity is $15 \, J/^{\circ}C$ and the specific heat capacity is $600 \, J/kg \cdot ^{\circ}C$.

When $300 \, J$ of heat is given to a body of mass $25 \, g$,its temperature rises from $25^{\circ}C$ to $45^{\circ}C$. What are the heat capacity and specific heat capacity,respectively?

Similar Questions

On what does the value of heat capacity depend?

On what factors does the required amount of heat depend to heat a given substance?

Two spheres made of the same substance have diameters in the ratio $1:2$. Their thermal capacities are in the ratio of:

Define specific heat capacity and write its $SI$ unit.

Why is water used in a rubber bag for fomentation on the body?

Vedclass Test Series

Exam Paper Generator

Online Exam Module