The kinetic energy of 20 , L of {H_2} gas is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Kinetic energy $E = 1.5 	imes 10^5 \, J$ and Volume $V = 20 \, L = 20 	imes 10^{-3} \, m^3$.The relationship between pressure $P$,kinetic

Vedclass · Accepted Answer

$5 	imes 10^6 \, N/m^2$

Vedclass · Answer

(D) Given: Kinetic energy $E = 1.5 	imes 10^5 \, J$ and Volume $V = 20 \, L = 20 	imes 10^{-3} \, m^3$.The relationship between pressure $P$,kinetic energy $E$,and volume $V$ for an ideal gas is given by $P = \frac{2}{3} \frac{E}{V}$.Substituting the values:$P = \frac{2}{3} \left( \frac{1.5 	imes 10^5}{20 	imes 10^{-3}} ight)$$P = \frac{2}{3} 	imes \frac{1.5}{20} 	imes 10^8$$P = \frac{2}{3} 	imes 0.075 	imes 10^8$$P = 0.05 	imes 10^8 = 5 	imes 10^6 \, N/m^2$.

The kinetic energy of $20 \, L$ of ${H_2}$ gas is $1.5 \times 10^5 \, J$. Find the pressure exerted on the container.

Similar Questions

The kinetic energy of one mole of a gas at $300 \, K$ is $E$. If the kinetic energy at $400 \, K$ is $E'$,then what is the ratio $E'/E$?

The relation between the pressure $(P)$,volume $(V)$,and average kinetic energy $(E)$ of a gas is

If the average kinetic energy of $O_2$ (molar mass $32$) is $0.048 \ eV$,what is the average kinetic energy of $N_2$ (molar mass $28$) at the same temperature (in $eV$)?

$A$ flask contains argon and chlorine in the ratio of $2:1$ by mass. The temperature of the mixture is $27^{\circ} C$. The ratio of average kinetic energies of two gases per molecule is (in $:1$)

The total random kinetic energy of $1 \,g$ of helium at $100 \,K$ will be $\left(R=8.3 \,J \,mol^{-1} \,K^{-1}\right)$. (in $\,J$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module