At a temperature of 27 , ^circ C,the rms spee | vedclass

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(A) The formula for the root mean square $(rms)$ speed of a gas is given by $v_{rms} = \sqrt{\frac{3RT}{M}}$.Given: $v_{rms} = 1930 \, m/s$,$T = 27 \,

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$H_2$

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(A) The formula for the root mean square $(rms)$ speed of a gas is given by $v_{rms} = \sqrt{\frac{3RT}{M}}$.Given: $v_{rms} = 1930 \, m/s$,$T = 27 \, ^\circ C = 300 \, K$,and $R = 8.31 \, J/(mol \cdot K)$.Rearranging the formula to solve for the molar mass $M$: $M = \frac{3RT}{v_{rms}^2}$.Substituting the values: $M = \frac{3 	imes 8.31 	imes 300}{(1930)^2} \approx \frac{7479}{3724900} \approx 0.002 \, kg/mol = 2 \, g/mol$.The gas with a molar mass of $2 \, g/mol$ is Hydrogen $(H_2)$.

At a temperature of $27 \, ^\circ C$,the $rms$ speed of a gas is $1930 \, m/s$. The gas is:

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