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(C) The coefficient of performance $(COP)$ of a refrigerator is given by the formula: $\beta = \frac{T_2}{T_1 - T_2}$,where $T_1$ is the temperature o

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$9$

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(C) The coefficient of performance $(COP)$ of a refrigerator is given by the formula: $\beta = \frac{T_2}{T_1 - T_2}$,where $T_1$ is the temperature of the hot reservoir and $T_2$ is the temperature of the cold reservoir in Kelvin.Given: $T_1 = 30^{\circ}C = 30 + 273 = 303 \ K$ and $T_2 = 0^{\circ}C = 0 + 273 = 273 \ K$.Substituting the values: $\beta = \frac{273}{303 - 273} = \frac{273}{30} = 9.1$.Rounding to the nearest integer,the coefficient of performance is $9$.

What is the coefficient of performance of a refrigerator operating between $30^{\circ}C$ and $0^{\circ}C$?

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